(3^5x-4)=(9^2x-3)

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Solution for (3^5x-4)=(9^2x-3) equation: 



(3^5x-4)=(9^2x-3)

We move all terms to the left:

(3^5x-4)-((9^2x-3))=0

We get rid of parentheses

3^5x-((9^2x-3))-4=0



We calculate terms in parentheses: -((9^2x-3)), so:

(9^2x-3)

We get rid of parentheses

9^2x-3

Back to the equation:

-(9^2x-3)



We get rid of parentheses

3^5x-9^2x+3-4=0

We add all the numbers together, and all the variables

3^5x-9^2x-1=0

We move all terms containing x to the left, all other terms to the right

3^5x-9^2x=1

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